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Post by Deleted on Oct 16, 2006 12:12:15 GMT
"A plane is standing on a runway that can move (some sort of band conveyor). The plane moves in one direction, while the conveyor moves in the opposite direction. This conveyor has a control system that tracks the plane speed and tunes the speed of the conveyor to be exactly the same (but in the opposite direction).
The question is:
Will the plane take off or not? Will it be able to run up and take off?"
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Post by Deleted on Oct 16, 2006 12:28:28 GMT
The plane will take off.
A plane doesn't push itself forward relative to the ground (like cars, trains, bikes etc. do) but it pushes against the air to get forward movement. The plane will still move forward (and eventually up) although the conveyor belt underneath it will reach insane speeds.
This is by the way the same reason a plane prefers to take off with a headwind, it's not groundspeed that's important but airspeed. With a headwind you get the speed of the wind as a free gift.
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Post by Deleted on Oct 16, 2006 12:38:28 GMT
Agreed. Having read the forum thread I found the teaser in, I also thought that the plane would take off as well.
The only thing I can't figure out is how much faster than normal the plane would have to go in order to get sufficient lift.
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Post by Deleted on Oct 16, 2006 13:01:39 GMT
The only thing I can't figure out is how much faster than normal the plane would have to go in order to get sufficient lift. No faster at all. Speed relative to the ground is irrelevant. The conveyor belt makes the groundspeed 'zero' but since only speed relative to the air is important it won't make a difference. The speed a plane has to reach to get lift is entirely dependent on wind speed. Taxiing on the conveyor belt may be impossible though because I believe there is some sort of pushing by the wheels involved in that. I had the infamous 15 minutes taxiing to Amsterdam's fifth runway last night and it sounds as if there is a small extra motor involved. The only question I still have is what speed the conveyor belt will reach.
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Post by agoodcuppa on Oct 16, 2006 13:04:27 GMT
A helicopter would have no trouble, nor would a Harrier.
However, assuming the "ground" upon which the plane is standing is always moving in exactly the opposite direction to the plane and at exactly the same speed then a conventional fixed wing aircraft will make nil airspeed and will not be able to achieve lift so will not take off.
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Phil
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Post by Phil on Oct 16, 2006 13:23:28 GMT
Brilliant question!!
The answer is: the conveyor belt is irrelevant.
As stated above it is airspeed that matters. Assuming zero headwind this is equal to groundspeed. But the plane is not driving itself along the ground by (tyre) friction - it is thrust against the air. So assuming the wheels are totally free to rotate the plane will take off in the normal way.
I like that one !!
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Post by tubeprune on Oct 16, 2006 13:53:21 GMT
If the plane wheels are turning only because it is being driven forward by its engines, and the conveyor belt is responding equally in reverse to the wheel rotation, the aircraft will remain fixed relative to the ground. It will receive no lift because it isn't moving through the air so it will stay on the ground. There won't be much air getting into the engines either.
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DrJimi
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Post by DrJimi on Oct 16, 2006 14:04:36 GMT
Exactly. The only thing this will accomplish is to wear out the tyres. There is zero relative wind over the wings. Try flying with a tailwind equivalent to your groundspeed. You will fly exactly the way a brick doesn't.
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Oracle
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Post by Oracle on Oct 16, 2006 14:04:47 GMT
In theory of the headwind was equal to the take-off speed required the 'plane will take off provided there is enough air flow into the engines. A Fiesler Storch has high-lift anti-stall devices and thus can actually hover in the air relative to ground because its stall speed is less than wind speed, and if wind speed was say 40 mph then it will hover. My late fatherin law actualy did one better than tghat once in an RAF Chipmunk and flew backwards, as wind speed was so strong that as stall speeds was exceeded, the 'plane flew and the speed was high enough to beat the prop thrust! An observer would see the 'plane fly backwards!
Oh! If a 'plane could actually temporarily lift off from the conveyor, the lack of resistance from the tyres would enable it to hop in the air, and then engine thrust would enable forward speed to increase airflow over and under the wings.
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Post by Deleted on Oct 16, 2006 14:05:47 GMT
If the plane wheels are turning only because it is being driven forward by its engines, and the conveyor belt is responding equally in reverse to the wheel rotation, the aircraft will remain fixed relative to the ground. No, it will still move forward because it is irrelevant what the conveyor belt does, as long as the wheels can turn. The wheels will turn twice as fast though, the plane moves forward and the belt backwards. Since the plane will move forward just like it would on a regular runway it will gain speed and eventually lift.
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Post by Deleted on Oct 16, 2006 15:14:55 GMT
No, it will still move forward because it is irrelevant what the conveyor belt does, as long as the wheels can turn. The wheels will turn twice as fast though, the plane moves forward and the belt backwards. Exactly! That's why I want to know how much faster the plane would have to go in order to get sufficient traction to begin moving air over its wings.
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Oracle
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Post by Oracle on Oct 16, 2006 16:46:56 GMT
It all depends on wind speed and direction. It depends on the plane as well: whether it has high-lift devices or not. The nearest analogy I can think of is the old WW2 aircraft carriers, before catapults. The ship would turn into wind, and would try and achieve say 35 mph wind over the deck say, which was basically the carrier's speed + wind speed. Planes would then virtually fly themselves off the deck with little forward speed. A forward speed over just 10 mph say may be sufficient to launch a plane off the conveyor. Of course an Autogyro, an aircraft with a rotary wing powered by the wind, can take off virtually straight away with just a few mph forward speed as the pilot manually turns the rotors, and even a small push from the rear prop will get it airborne.
Actually on reflection, an aircraft could in fact take off without even moving! If there is sufficient wind speed, as experienced in hurricanes or storm cells, then the wings will lift even though the plane is stationery. If however the plane is on the conveyor, and there is nil wind or less than 4 knots, something I have only experienced one in a Piper PA28, then it ain't going anywhere! It is stalled on the ground. That's what you aim to achieve when landing, rounding out at the height of a double-decker bus, throttle back, and controlling descent with the stick. The air cushioned under the wings acts in the wing-in-ground-effect and the plane then stalls on the ground: if not the plane will bounce!
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Post by agoodcuppa on Oct 16, 2006 17:41:56 GMT
That's why I want to know how much faster the plane would have to go in order to get sufficient traction to begin moving air over its wings. Aircraft don't have traction. The wheels are only there to allow a plane to roll along the ground (In some parts of the world, aircraft have floats or skis for operating from water or snow.) Movement is the result of the jet thrust or airscrew acting on the atmosphere. Hence an aircraft needs air moving backwards (relatively) over the wings to acquire and maintain flight. This is the principle a kite uses to fly. Thus the "conveyor belt" moving in the opposite direction will prevent the aircraft from moving forward and create an airflow over the wings.
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Post by agoodcuppa on Oct 16, 2006 17:46:48 GMT
Since the plane will move forward just like it would on a regular runway it will gain speed and eventually lift. If the belt is matching the a/c's speed(but in the oppposite direction) how will that happen?
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Oracle
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Post by Oracle on Oct 16, 2006 18:10:51 GMT
My closing thoughts are well they were but I have risen to a challenge!:
a) There will always have to be a time delay between the aircraft speed increasing through thrust, propellor wash or air flow and the belt speeding up to comenstae. This means that it would be theoretically possible to move forward for a limited period of time. This might be sufficient to take off. b) Even if the aircraft is stationary relative to ground, if windspeed can be increased it will take off if the lift component is sufficient. It is thus irrelevant if the aircraft is for all intents and purposes not advancing.
As I said before, this analogy does happen in the real world, when forward speed is matched or exceeded by wind or air speed. It is the air flow above and below the wing and the pressure differential that matters. That differential provides lift, or in the reverse direction, groundforce as in a racing car's airofoils. If a powerful fan was put in front of the ensemble, sufficient air flow could be induced to cause the 'plane to lift off. The same would apply if we had to use as I mentioned before an aircraft carrier, or even a fast-moving road vehicle [that has been done..to take off and land]. It's the wind or air speed over the wings that determines whether it can take off or not.
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Post by agoodcuppa on Oct 16, 2006 18:19:46 GMT
b) Even if the aircraft is stationary relative to ground, if windspeed can be increased it will take off if the lift component is sufficient. It is thus irrelevant if the aircraft is for all intents and purposes at rest. To arrive at your conclusion you've had to introduce an "if" which wasn't there at the start. Apart from aircraft carriers, the only way a plane can generate sufficient speed to generate lift and defeat gravity is to make forward movement relative to the wind, which in the vast majority of cases also means moving over the ground. The Fiesler Storch and similar a/c are known about and accepted, but they are unusual.
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Oracle
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Post by Oracle on Oct 16, 2006 20:20:39 GMT
Well, I can say that I have personally witnessed b), well almost! HMS Daedalus, 50th D-Day anniversary [Lee on Solent airfield] : the Fleet Air Arm's Fairey Swordfish took over against a strong headwind in just a few feet at slow speed. I have also seen a friend's gyrocopter, G-GYRO which he made himself take off instantaneously after he had self-rotated the rotors. However, we are not talking of rotary craft here, presumably. I also remind that an aircraft can lift off even if tied down! Witness Hurricane Andrew which devastated a USAF base. It is wind or rather more correctly, air speed over a lifting surface that provides lift or creates downforce. I should also add in here that air temperature can also affect lift, as can air pressure. But that's getting off the nub of the Teaser. Getting back to the conundrum, the aircraft is said to be on a runway [and at this point you have to read it carefully and think laterally]. By that notion it is implied that there is, unless there is a dead calm, some form of air flow is available. Apart from physically moving the whole ensemble, that is aircraft and conveyor, on some form of road trailer to get the flow going [which is of course one asnwer to the condundrum] then that aircraft is not going anywhere until the air flow over the wings reaches critical point. That could be achieved by a fan or series of fans or waiting for wind velocity to increase. Therefore my answer to the question: Will the plane take off or not? Will it be able to run up and take off?" is "It is assumed that as it is a runway, and it is in the open air because the aircraft is hoped to take off, there must be a wind available although not necessarily at any given time. Short of moving the conveyor on a road trailer or sending it down an inclined plane or off a cliff, the aircraft will not be able to take off unless its critical lift component can be exceeded by either augmenting airflow by means of a fan or turbine, or by waiting until the wind speed is high enough. The question does not mention types of aircraft but some with supercritical wings and other higher-lift devices would require less air flow than more conventional types". I should of course have pointed out that a sloping runway, and by golly I have been on one...Compton Abbas is on a hillside...or using a catapult to launch the conveyor would also assist air flow but that's taking things to extreme. My reply to the question is based on a little bit of aeronautical engineering and a heck of a lot of flying over the years in light aircraft..over land and water!
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Post by Deleted on Oct 16, 2006 21:43:12 GMT
Since the plane will move forward just like it would on a regular runway it will gain speed and eventually lift. If the belt is matching the a/c's speed(but in the oppposite direction) how will that happen? The engines push the aircraft forward against the air, not against the ground. As long as the aircraft is able to roll it will move forward, the conveyor belt has no influence whatsoever. A plane is not a car and doesn't rely on friction with the ground. The moving belt removes the ground friction but since ground friction is irrelevant for planes the belt is not preventing the plane to move forward. The only thing that matters is airspeed, as long as the speed of the air from head to tail is above a certain speed (dependent on the size of the plane and design of the wings etc.) the plane will take off. Theoretically a plane can take off without having wheels at all. If there is enough natural headwind to create lift a plane could take off from standstill. This can be seen with smaller planes during tornado's and could even be theoretically possible with a jumbo jet. The only reason it doesn't happen with 747's is because natural winds up to those speeds don't occur as far as I know. Just picture yourself standing next to the conveyor belt, looking at the plane and then think of the engines pulling the air in front of them in and pushing it out at the back thereby pushing the plane forward.
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Post by agoodcuppa on Oct 16, 2006 21:58:03 GMT
The engines push the aircraft forward against the air, not against the ground. As long as the aircraft is able to roll it will move forward, the conveyor belt has no influence whatsoever. The OP quite explicitly states that the speed of the belt is matched to the speed of the aircraft. Therefore as the a/c gains speed so does the belt, therefore no forward movement relative to starting point, therefore no increased airflow over the wings. True, hence sea and ski planes. Yes it is, because as the a/c speed increases so does the belt's. Quite true, but until the a/c is airborne it needs to have groundspeed as well. Since the belt is running at the same speed in the opposite direction the a/c is unable to gain groundspeed. In Canada floatplanes are widely used. Until we built large airports seaplanes were amongst the largest commercial a/c. en.wikipedia.org/wiki/Flying_boatwww.photovault.com/Link/Technology/Aviation_General/show.asp?tg=TAGVolume06/TAGV06P13_17True.
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Oracle
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Post by Oracle on Oct 16, 2006 22:10:29 GMT
I am off to bed as I have just seen a large rodernt in our kitchen and the pest men have to come again...I want some sleep! Yes there is a belt or form of conveyor but it will never be able to instantaneously match the aircraft rolling speed...there will always be a delay whilst the system, however it is calculated, speeds up or slows down. There will always be a period of delay whilst the match is made. In theory if the aircraft had enough power it would be able to accelerate the conveyor which is playing catch-up, and take off. This would of course rely on some reasonable period of delay, as aircraft are not exfceedingly good at acceleration.
However if we strictly apply the criteria laid down in the conundrum, we just have to wait for a very windy day! For a 747, a hurricane! Oh! We would then have to swivel said conveyor round to face directly into the wind. But you knew that!
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Post by Deleted on Oct 16, 2006 22:37:23 GMT
The engines push the aircraft forward against the air, not against the ground. As long as the aircraft is able to roll it will move forward, the conveyor belt has no influence whatsoever. The OP quite explicitly states that the speed of the belt is matched to the speed of the aircraft. Therefore as the a/c gains speed so does the belt, therefore no forward movement relative to starting point, therefore no increased airflow over the wings. There is a forward movement relative to anything that is not attached to the runway/belt (i.e. passengers looking at the plane from the terminal building, signs and lights next to the runway and -very important- the wind). Why would a plane need groundspeed? It just needs airspeed, if the natural airspeed/wind is not enough (which it hardly ever is) it creates it by pulling itself forward. As a side effect of this it usually also creates groundspeed but that is a byproduct and not necessary for lift. It is important to note that the plane pulls itself forward by pulling at the air in front of it. The air is not attached to the belt so the belt has no effect on it.
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Post by agoodcuppa on Oct 16, 2006 23:07:21 GMT
It is important to note that the plane pulls itself forward by pulling at the air in front of it. Or a jet pushing, but we agree on how an a/c engine causes movement. True, but the a/c is sitting on the belt and as the a/c gains speed by its engines acting on the air the belt also increases speed.
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Post by agoodcuppa on Oct 16, 2006 23:46:43 GMT
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DrJimi
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Post by DrJimi on Oct 17, 2006 1:13:35 GMT
With appropriate humility I retract my earlier answer. I was focusing on speed not force. It will indeed take off normally, however wheel speed will be approx. twice groundspeed. I found this explanation most clear: ooine.com/index.cfm?commentID=154I mentally set up the required condition in 2 steps to see the effect. First, hold the plane still (e.g. hold the wings). Brakes are off. Crank up the belt to 20mph. Plane motionless (we're holding it still), wheel speed 20mph (assumes good tire/belt friction and zero wheel bearing friction). Now release the plane and add enough power for 20mph ground speed. At this point conditions are met - plane speed = 20, belt speed = -20, but wheel speed = 40. Plane is moving ahead at 20mph. Continue accel to V1 (or V2+10 for safety) - say 130 for a 737. Now plane speed = 130, belt = -130, wheel speed = 260. Liftoff. It's the force that matters. The belt is irrelevant, other than it roughly doubles the wheelspeed. I think.
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